Why is my ternary expression not working?

Why is my ternary expression not working? "I am trying to set a flag to show or hide a page element, but it always displays even when the expression is false. $canMerge = ($condition1 && $condition2) ? 'true' : 'false'; ... <?php if ($canMerge) { ?>Stuff<?php } ?> What's up?"
Asked by: Guest \| Views: 281

Total answers/comments: 4

Comments display order:

Guest [Entry]

"This is broken because 'false' as a string will evaluate to true as a boolean.

However, this is an unneeded ternary expression, because the resulting values are simple true and false. This would be equivalent:

$canMerge = ($condition1 && $condition2);"

Guest [Entry]

"The value of 'false' is true. You need to remove the quotes:

$canMerge = ($condition1 && $condition2) ? true : false;"

Guest [Entry]

"Seems to me a reasonable question especially because of the discrepancy in the way PHP works.

For instance, the following code will output 'its false'

$a = '0';

if($a)
{
echo 'its true';
}
else
{
echo 'its false';
}"

Guest [Entry]

"$canMerge = ($condition1 && $condition2);

then

if ($canMerge){
echo ""Stuff"";
}"