Provide a higher degree equation with substitution that can be transformed to quadratic equation such

"Answer:

Instructions: Choose the letter of the correct answer. Write your chosen answer on a separate sheet of paper. If the answer is not found among the given choices, write your own answer. A. Transform the following quadratic equations to its standard form. 1. (x)(x) = 4 A. 2x 2 = 4 C. x 2 − 4 = 0 B. 2x 2 − 4 = 0 D. x 2 + 4 = 0 2. x(x + 3) = 4 A. x 2 + 7 = 0 C. x 2 + 3x − 4 = 0 B. 2x − 1 = 0 D. x 2 + 3x + 4 = 0 3. (x + 3)(x − 4) = 5 A. x 2 − x + 12 = 5 C. x 2 − x + 17 = 0 B. x 2 − 7x + 12 = 5 D. x 2 − x − 17 = 0 4. (2x − 3)(4x − 5) = −6 A. 8x 2 − 22x + 9 = 0 C. 8x 2 − 22x − 21 = 0 B. 8x 2 − 22x + 9 = 0 D. 8x 2 − 22x + 21 = 0 5. (x − 6) 2 = 7 A. x 2 − 12x + 43 = 0 C. x 2 − 12x + 29 = 0 B. x 2 − 12x − 43 = 0 D. x 2 − 12 − 29 = 0 6. (x − 7) 2 + (x + 8) 2 = 9 A. x 2 + x + 52 = 0 C. x 2 + x + 61 = 0 B. x 2 − x + 52 = 0 D. x 2 − x + 61 = 0 7. 2x2 5 + 5x 4 = 3 A. 8x 2 + 25x + 60 = 0 C. 7x 2 + 9x + 12 = 0 B. 8x 2 + 25x − 60 = 0 D. 7x 2 + 9x − 12 = 0 8. 6x x+5 + x−5 2 = 3 A. x 2 + 6x − 45 = 0 C. x 2 + 6x + 55 = 0 B. x 2 + 6x + 45 = 0 D. x 2 + 6x − 55 = 0

Sorry po kung mali need ko lng po kase"